博客
关于我
强烈建议你试试无所不能的chatGPT,快点击我
HDU2629 Identity Card【MAP+水题】
阅读量:7171 次
发布时间:2019-06-29

本文共 2196 字,大约阅读时间需要 7 分钟。

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4120    Accepted Submission(s): 1567
Problem Description
Do you own an ID card?You must have a identity card number in your family's Household Register. From the ID card you can get specific personal information of everyone. The number has 18 bits,the first 17 bits contain special specially meanings:the first 6 bits represent the region you come from,then comes the next 8 bits which stand for your birthday.What do other 4 bits represent?You can Baidu or Google it.
Here is the codes which represent the region you are in.
 
However,in your card,maybe only 33 appears,0000 is replaced by other numbers.
Here is Samuel's ID number 331004198910120036 can you tell where he is from?The first 2 numbers tell that he is from Zhengjiang Province,number 19891012 is his birthday date (yy/mm/dd).
Input
Input will contain 2 parts:
A number n in the first line,n here means there is n test cases. For each of the test cases,there is a string of the ID card number.
Output
Based on the table output where he is from and when is his birthday. The format you can refer to the Sample Output.
Sample Input
 
1 330000198910120036
Sample Output
 
He/She is from Zhejiang,and his/her birthday is on 10,12,1989 based on the table.
Author
Samuel
Source

问题链接:。

题意简述:参见上文。

问题分析:解释身份证上省份和生日信息。

程序说明:(略)

题记:(略)

AC的C++语言程序如下:

/* HDU2629 Identity Card */#include 
#include
#include
#include
using namespace std;map
m;int main(){ int n; string id; m[33] = "Zhejiang"; m[82] = "Macao"; m[11] = "Beijing"; m[54] = "Tibet"; m[71] = "Taiwan"; m[21] = "Liaoning"; m[81] = "Hong Kong"; m[31] = "Shanghai"; cin >> n; while(n--) { cin >> id; int region; region = (id[0] - '0') * 10 + (id[1] - '0'); printf("He/She is from %s,and his/her birthday is on ", m[region].c_str()); printf("%c%c,%c%c,%c%c%c%c", id[10], id[11], id[12], id[13], id[6], id[7], id[8], id[9]); printf(" based on the table.\n"); } return 0;}

转载于:https://www.cnblogs.com/tigerisland/p/7563630.html

你可能感兴趣的文章
OceanBase在蚂蚁金服的智能运维实践之路
查看>>
我的友情链接
查看>>
磁盘分区和目录结构
查看>>
grep、egrep、fgrep及正则表达式
查看>>
我的友情链接
查看>>
熟悉dstat命令用法
查看>>
kali linux字体渲染和infinality安装配置
查看>>
高效出去List集合和数组中的重复元素
查看>>
我的友情链接
查看>>
grep常见选项及命令
查看>>
nodejs终端的坑--新手向
查看>>
pycharm修改默认__author__ = '$USER'
查看>>
DNS服务的原理与配置(详细图文教程)
查看>>
threejs 之box贴图--6个 面集中在一个图片上
查看>>
Exchange Server 2010安装测试
查看>>
设计模式第九课 策略模式
查看>>
给定两个排序后的数组A和B,其中A的末端有足够的缓冲空间容纳B。将B合并入A并排序...
查看>>
FFmpeg avcodec_version函数使用
查看>>
一步步手动构建小于10M的类嵌入式Linux系统
查看>>
saltstack细节要点
查看>>